[tahoe-dev] Tahoe-LAFS is widely misunderstood

[Chris Palmer]

Shawn Willden writes:

> The same situation applies, though.  For any given expansion factor E,
> assuming moderately high server reliability, you'll get better net
> reliability with N/E-of-N than with 1-of-E.  As E goes up, the level of
> server reliability required for break-even declines, and the advantage of
> erasure coding increases.

I don't understand what you mean. Can you please fill in an example with
real numbers?

Isn't my scheme simply the most reliable and most expensive form of erasure
coding?


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